SOLVED: Starting with x1 = 2, find the third approximation X3 to the root of the equation x Zx - 5 = 0. SolutionWe apply Newton's method withf(x) = x3 2x - 5and f'(x)So the iterative equation becomes 2*0 Xn l XnWith n = 1, we have x,3 2*1 X2 = X123 2(2) - 5 = 2 -Then with n = 2, we obtain X23 2x2 X3 Xz-(Round to four decimal places:)It turns out that this third approximation X3is accurate to four decimal places
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